5x²+5y²+8xy-2x+2y+2=0,求x, y?

5x²+5y²+8xy-2x+2y+2=04x²+8xy+4y²+x²-2x+1+y²+2y+1=0(2x+2y)²+(x-1)²+(y+1)²=0所以(2x+2y)²=0或(x-1)²=0或(y+1)²=0得x=1,y=-1